√ダウンロード 5−2×5−3 109855-5 2 5 3*5 2
Use y = −6, and z = 5 14) p(q ÷ 3 − p);Usex =3, z =2 17) k × 32 − (j k) − 5;3 × (7 − 5) 3 − 8 5 × 2 Stepbystep solution Step 1 of 4 Consider the expression, The objective is to evaluate the abovementioned expression using the concept exponent rule And if necessary, then apply order of operation means BODMAS rule Chapter 17, Problem 35E is solved
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5 2 5 3*5 2- a 10(25−10)÷5 b (4÷25−5−2) c @41 2 31 2 A÷ @7 12 −1 2 A÷2 d )45÷3×5−( e 2 5 7−1 2 ×8 2 Solve the following algebraic expressions using the given value/s of the variable a 2 (4𝑝5𝑦)−3𝑝7𝑦) if p = 1;7 −1 5 2 3 1−6 4 3 7 −1 5 2 3 1=70 −19 5 −39 44 21 11 8 22 7) Suppose is an 𝑛×𝑛 matrix such that 3−4 2−2 8𝐼=𝒪 Show that is nonsingular and −1=1 8 (2𝐼4 − 2) Solution Rearrange the given equation ( 2−4 −2𝐼)=−8𝐼, then divide both sides by −8 to get 1 8
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= 7 2 − 4 × 2 × 6 = 49 − 48 ∴ D = 1 (ii) 3 x 2 − 2 x 8 = 0 Comparing with a x 2 b x c = 0, we get a = 3, b = − 2, c = 8 Thus, the discriminant D = b 2 − 4 a c = (− 2) 2 − (4 × 3 × 8) = 4 − 96 ∴ D = − 92 (iii) 2 x 2 − 5 √ 2 x 4 = 0 Where a = 2, b = − 5 √1)_Worksheets1docx Math 128/118 Worksheets Weeks 1 2 3 Worksheet#1 – Operations with Signed Numbers 1 3 5 7 9 11 13 15 17 −2× 3= 0 4= 7 ×−2−−5 3 −4−59 1 − 54 5 − 2 3 1 − 1 0 −5 × −9 45 −9×654 10×−440 −3×−6 18 8×−1080 64÷− −60÷610 −24÷−3 8 −16÷ 42÷−67 Sets with similar terms MDS Mental Math Integers Set 2 15 terms MikeShieldsRocks TEACHER
Ex 11, 1 Using appropriate properties find (ii) 2/5×(−3/7) – 1/(6 ) × 3/21/14 × 2/5 2/5×(−3/7) – 1/(6 ) × 3/21/14 × 2/5= 𝟐/𝟓× (−3/7) 1/14Correct answer to the question Need answers quickly need it step by step (−5)2 −2×(−9)6= (−9)−(−8)2×42= 8÷(−4)×(−6)2 7= 10×5−(−6)2 (−8Write the correct answer from the given alternative to make the following statemets true m 2 n × n 2 m = Medium View solution > 5 x − 5 x − 4 = 1 5 6 0 0 then find x 3 Easy View solution >
Question (52×10^−2)−(×10^−3) Simplify the expression and write answer in scientific notation Found 3 solutions by Theo, greenestamps, MathTherapy Respuesta 1) (−7) × (4) ÷ (−2) 15 (28)÷(2)15 1415 = 29 2) (−12) × (−14) ÷ (−3) ( 168)÷(3) = 56 3) (−5) (−9) − (−8)Use p=6,q=5,r=5 15) y− 4− y − (z − x);
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Evaluate (i) (8−1× 53)/2−4 (ii) (5−1× 2−1)×6−1 Exponential notation is a powerful way to express repeated multiplication of same number Specifically, powers of 10 in a manner that it is easy to useY = 2 b 3 × @5 𝑛 −1 3 A if n = 2 c (1 2 ×10 −2)3×2 if m = 2 3 d )1 8 (−5)2 ×3÷59= 4 × (−6) ÷ 8 33= 1 See answer Advertisement Advertisement khsalehawaz is waiting for your help Add your answer and earn points ohsangwooandyoon ohsangwooandyoon Answer 1 14 2 331 454 50 64 712 0 93 1030 Stepbystep explanation hoped it helps^^ Thanks
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Usex =3, y=1,z =6 16) 4z − (x x − (z − z));5 3 can be written as −3 2 −3×3 2×3 = −9 6 5 3 5×2 3×2 = 10 6 Five rational numbers between −3 2 and 5 3 = five rational numbers between −9 6 and 10 6 ∴, Five rational numbers between −9 6 and 10 6 = −1 6,2 6,3 6,4 6,5 6 (iii) 1 4 and 1 2 Let us make the denominators same, say 24 ie, 1 4 and 1 2 can be written as 1 4 1×6 4×6 = 6 24 1 2 1×12 2×12 = 12 24You can rewrite the relation R { (3, −5), (1, 2), (−1, −4), (−1, 2)} as the rule The range of relation are all y that are maped to In your case, the range of relation is the set Answer correct choice is B Answerd by caagrawal 1 month ago 58 47 × You can't Rate this answer because you are the owner of this answer
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Please visit EffortlessMathcom Multiplying and Dividing Integers Find each product(−3)9× (−3)5= Exercise 8 Let 𝑥𝑥 be a positive integer 9 If (−3) × (−3)𝑥𝑥= (−3)14, what is 𝑥𝑥?Virtual School Title Yr 9 GCSE Maths 1 Order of Operations and Negative Numbers
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1) (−9) × 5 22 2) 4 − (1 − 8 − 3) 3) 6 × 7 5 − 7 4) 8 − 5 − 8 8 5) (−10) 6 − 1 − 8 6) (−2) − (8 × 10 9) 7) (−1) − 3 − (−65) 42−6×2 10) 125×18÷9 Evaluate 1) 32×42 5) 5÷8−3×26 2) 9÷(22−4÷4) 6) 5×86÷6−12×2 3) 36 ×( 54) ÷7) 180 8− 4) 36−3×4 15−9÷3 8) 22×5 215−3×4 Evaluate You must justify your answer 1) 272×5=37 4) 10×÷23=40 2) 19−6×2=26 5) 5−9×12−17= 3) 219÷3=10 6) 3×7 −22×9 =81 Insert brackets to obtain8) 5(b a)1 c;
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Use y=5,z =4 14) p(q − r)(6 − p);Click here👆to get an answer to your question ️ Simplify 3^5 × 10^5 × 125/5^7 × 6^51 8−(19−(25)−7)=−11 2 2 × 7 × 11−12÷3=150 3 (37)÷(7−12)=−2 4 8 × 562=76 5 9÷3 × 7−237= 6 812÷66=16 7 (72−32)÷8=5 8 2(5)5=50 9 3(5)22(5)1=86 10 (1 2−2)=1
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23i = 2−3i Divide both sides by 13 1 23i = 2−3i 13 In general, 1 abi = a−bi a2 b2 Now for division 5−6i 23i = (5−6i)× 1 23i = (5−6i)× 2−3i 13 = (5−6i)(2−3i) 13 = −8/13−27/13i Problems Compute AB and A−B and AB and A/B for • A = 2i and B = 1−i • A = 12i and B = 4−3i • A = 2−5i and B = −27i 12 x 6 − (2 x 5) = 2 (x − 2) × 3 (x − 2) × 2 To find the opposite of 2x5, find the opposite of each term To find the opposite of 2 x 5 , find the opposite of each term0 (18)×10−5 S 23×10−10 inverse of conductance quantum G−1 0−10 Josephson constant 12e/h K J (30)×10 9Hz V
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2 5 − 5 2) = −19 5 𝑖(−21 10) = −19 5 − 21 10 𝑖 Overall Hint Subtract the terms then group the constants and the terms with the imaginary then write it in the form of aib 7 Express the given complex number in the form 𝑖×, ÷' and exponents" 3, 8 3 1, 4 7 5, 2 3 2 − − − − x xy y x x xy x Like Terms Terms that are constants or terms that contain the same variables raised to the same exponents We can combine and simplify only like terms Like Terms as constant –4, 154, 374, –037, 𝜋, ⋯ Example 4 Simplify and write the answer in the exponential form (i)〖〖 (2〗^5 "÷ " 2^8)〗^5 × 2^(−5)〖〖 (2〗^5 "÷ " 2^8)〗^5 × 2^(−5)= (2^5/2^8 )^5
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View Characteristics of functionsdocx from SCIENCE CCP234 at Virtual Highh School 1 a First of all, simplify each of the radical terms before adding ¿ 2 √9 × 35 √ 4 ×2−3 √ 9× 2 4Use p = −6, and q = −3 1 ©z 62j0 R1T2s TK VuOt baQ TSzoUfjt fw LaWrGeW eLFLuC ij Q 8A Dl NlY Lr Gihg OhKtasS HrPeLs be 7r fvmeDd74 J 1M da od veO TwaictKhD QIJn NfKitnLi gt Red WAHljg 2ejbQrxa y d25(xiv) (243)2/5 ÷ (32)−2/5 Solution = (3 × 3 × 3 × 3 × 3)2/5 ÷ (2 × 2 × 2 × 2 × 2)−2/5 = 2(3 5) /5 ÷ (2 )−2 = 35× (2 /5) ÷ −22 −2 )×5 = 32 ÷ 2 = 23 × −2(1/2 ) = 32 × 22 = 3 × 3 × 2 × 2 = 36 (xv) (−3)4 − (∜3)0 × (−2)5 ÷ (64)2/3 Solution
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Math Worksheets Name _____ Date _____ So Much More Online!5 51 © 12 Pearson Education, Inc Eigenvalues and Eigenvectors EIGENVECTORS AND EIGENVALUES1 3 × (2 × 43) ÷ 4 = 96 2 (43 2 − 1) = 65 3 (5 × 3) × 1 5 = 4 (72 − 23 − 6) = 35 5 (53 7) × 2 = 264 6 4 − (9 22 ÷ 2) = 7 7 6 − (9 × 13) 5 = 62 8 (2 ÷ 4 × 8) = 4 9 8 − (3 43) × 5 = 327 10 5 × (23 − 8) × 5 = 0 11 (9 × 9 5) = 86 12 (1 4 − 4) = 1 13 5 × (4 ÷ 12 8) = 60 14
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Simplification Questions & Answers for Bank Exams (−5) { − (−2) × (−8)}= ?31−11−(−4−510) −4 −315·4(−186)× ∗2 −− 047−26·(517− ÷0044) (3 1 4 ·5 3 13 −7 1 3 ·2 2 11)−3375·1 1 9 −3 1 4 021 075−06 − 7 6(1 15 3 8 29 40) 28 65 ·(9 2 − 25 7) #duqnwvg xcnwgu −108 −4 5−−3 − 11 4 −2−4 2 −5) 38 × 101 6) 368 × 103 7) 975 × 102 8) 6928 × 10−3 9) 91 × 104 10) 1407 × 106 11) 1038 × 10−3 12) 102 × 101 13) 49 × 100 14) 1458 × 1016 15) 9766 × 10−9 16) 9064 × 10−27 17) 53 × 10−9 18) 2873 × 10−2 19) 5313 × 10−1 ) 6662 × 10−4 21) 38 × 10−2 22) 24 × 108 23) 1176 × 103 24) 2
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Evaluate (i) (2 − 3 × 5 4) (5 9 × 3 − 10) (i i) (2 × 1 4) − (− 18 7 × − 7 15) (i i i) (− 5 × 2 15) − (− 6 × 2 9) (i v) (8 5 × − 3 2) (− 3 10 × 9 16) Mathematics Q 2(3 × 6) − 5 = 13 14 6 × (2 ÷ 1) ÷ 1 = 12 15 (23 − 9 − 8) ÷ 3 × 3 = 9 16 23 ÷ (7 ÷ 7 ÷ 8) = 64 17 (6 62) × 3 = 126 18 (3 1) × 8 × 4 = 128 19 (73 × 4) 7 = 1379 62 − 3 × (32 × 2) 5 = 13 Title Microsoft Word ordofopdoc Author AnswerStepbystep explanation1 =86=142 184=3 2×(−6)2 7=12×27=247=314 50(−6)2 (−8)==628=545 (22)× (−3)3=0× (−3)3=06
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(i) (25×t −4)/(5 −3 ×10×t −8) (t ≠ 0) (ii) (3 −5 ×10 −5 ×125)/(5 −7 ×6 −5) Solution The exponent of a number shows how many times the number is multiplied by itself (i) (25 × t −4)/(5 −3 × 10 × t −8) Let's express 25 and 10 in terms of their prime actors as shown below, = (5 2 × t −4)/(5 −3 × 5 × 2 × t −8 ) = (5 2 × t −4)/(5 −3 1 × 2 × t⋄ Example 51(a) Find T −3 5 for the transformation defined above T −3 5 = −35 5 (−3)2 = 2 5 9 It gets a bit tiresome to write both parentheses and brackets, so from now on we will dispense with the parentheses and just write T −3 5 = 2 5 9 At this point we should note that you have encountered other kinds of transformations2 2 2 2 8 64 5 8 5 25 − × = = EXERCISE 121 1 Evaluate (i) 3–2 (ii) (– 4)– 2 (iii) 1 2 5 − 2 Simplify and express the result in power notation with positive exponent (i) (– 4)5 ÷ (– 4)8 (ii) 1 23 2 (iii) ( )− × 3 5 3 4 4 (iv) (3– 7 ÷ 3– 10) × 3– 5 (v) 2– 3 × (–7)– 3 3 Find the value o f
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Find −25 ⋅ 36 −25 × 36 1 5 0 7 5 0 −90 0 The product is −9 EXAMPLE 2 Multiplying Rational Numbers The product is negative Multiplying and Dividing Rational Numbers Words To multiply or divide rational numbers, use the same rules for signs as you used for integers Numbers − 2 — 7 ⋅ 1 — 3 = −2 ⋅ 1 — 7 ⋅ 3 = −2 10 × 4 − 5 = 6 3 24 ÷ 8 = 4 − 5 × 4 = 8 1 6 × 5 = 10 50 − 10 ÷ 2 = OPS 1 Math Plus Motion LL36 × 10 −5 60 × 10 −4 = (36 60) × (1,5), (2,10), (3,7), and (4,14) Each of these points can be plotted on a graph and connected to produce a graphical representation of the dependence of y on x If the function that describes the dependence of y on x is known, it may be used to compute x,y data pairs that may subsequently be
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05×10−3 25×10−3 125×10−3 G Δ å ′=−481 k mol b For the muscle described, what is the maximum amount of mechanical work it can do per mole of ATP hydrolyzed? See the answer See the answer See the answer done loading Find the cross product a×b where a=〈5,−5,−2〉 and b=〈0,1,−3〉 a×b= Find the cross product c×d where c=5i−1j5k and d=−3i1j1k c×d= Expert AnswerIn general, if 𝑥𝑥 is any number and 𝑚𝑚, 𝑛𝑛 are positive integers, then 𝑥𝑥𝑚𝑚∙𝑥𝑥𝑛𝑛= 𝑥𝑥𝑚𝑚 𝑛𝑛 because 𝑥𝑥𝑚𝑚× 𝑥𝑥𝑛𝑛= ( 𝑥𝑥⋯ 𝑥𝑥)
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10 ÷2 = 5 7) 3 ×−6 = 18 8) −24 ÷−8 = 3 9) −12 ×9 = 108 10 ) 10 ÷10 = 1 11 ) 7 ×−6 = 42 12 ) −9 ÷−1 = 9 13 ) −6 ×−5 = 30 14 ) 36 ÷3 = 12 15 ) 4 ×−4 = 16 16 ) −27 ÷−9 = 3 17 ) −4 ×6 = 24 18 ) 56 ÷8 = 7 19 ) 5 ×−7 = 35Intermediate Algebra Skill Writing Numbers in Standard Notation Write each number in standard notation 1) 97 × 10−3 2) 46 × 10−5 3) 76 × 10−5 4) 33 × 102 5) 6 × 10−2 6) 59 × 10−5 7) 9 × 100 8) 6 × 10−3 9) 52 × 10−3 10) 2 × 102 11) 605 × 10−2 12) 75 × 10−2 13) 96 × 10−7 14) 321 × 106 15) 29 × 10−1 16) 98 × 100𝑤 à ë, çℎ æ ì æ ç à=−𝑤 à ë, â á çℎ æ è å å â è á 𝑖 á𝑔 æ å ′=481 k mol −𝑤 å é, à ë=481 k mol
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